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- Path: engnews1.Eng.Sun.COM!taumet!clamage
- From: wikman@research.nokia.com (Johan Wikman)
- Newsgroups: comp.std.c++
- Subject: Re: Problem with template overloading.
- Date: 23 Feb 1996 15:55:23 GMT
- Organization: ?
- Approved: clamage@eng.sun.com (comp.std.c++)
- Message-ID: <9602231434.AA15034@garlic.spices>
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- Originator: clamage@taumet
-
- In article <4gi7h0$l0@engnews1.Eng.Sun.COM> clamage@Eng.Sun.COM (Steve Clamage) writes:
-
- > In article AA11584@garlic.spices, wikman@research.nokia.com (Johan Wikman)
- > writes:
- >
- > >I'd like to be able to have a class and a template with the same name
- > >in the same scope.
- >
- > class A { ... };
- >
- > template <class T>
- > class A {
- > void foo() { .... A ... }
- > };
- >
- > In A<T>::foo, I use the identifier "A". Does that refer to the template
- > or to the class? In order not to break all existing code, it must
- > refer to the template.
-
- Interesting, I always thought you had to use A<T>. Now that I tried
- it, all compilers I have access to (HP, gcc and MS VC++) accepted both
- A and A<T>. What does the standard say? Are both versions allowed?
-
- > Perhaps you can think of a special syntax that won't change the meaning
- > of existing code, or we could say that you can't refer to class A anywhere
- > in the scope of template A.
-
- No, I won't even try. But I definitely find using A<T> within the
- definition of a template's function more intuitive than just using
- A. Making A<T> a requirement certainly wouldn't break my code;-).
-
- --
- johan.wikman@research.nokia.com
-
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